The average diameter of sand dollars on a certain island is 5.00 centimeters with a standard deviation of 0.90 centimeters. If 16 sand dollars are chosen at random for a collection, find the probability that the average diameter of those sand dollars is more than 4.73 centimeters. Assume that the variable is normally distributed.
Accepted Solution
A:
Answer:the probability that the average diameter of those sand dollars is more than 4.73 centimeters is 0.5910Step-by-step explanation:Given information:mean, x = 5standard deviation, σ = 0.9number of sample, n = 16now we calculate the probability that the average diameter of those sand dollars is more than 4.73 centimeters.P(x>4.73) = P (z > (4.73 - x) / (σ [tex]\sqrt{n}[/tex]) = P (z > (4.73 - 4) / (0.9 [tex]\sqrt{16}[/tex]) = P (z > 0.203) = 0.5910