Perimeter of quadrilateral

Answer:The answer to your question is:  14 + 2√40  = 26.6 unitsStep-by-step explanation:DataA ( -5, 4)     B (-3, -2)     C (4, -2)     D (2, 4)Formulad = √(x2 - x1)² + (y2 - y1)²Perimeter = dAB + dBC + dCD + dADProcessdAB = √(-3 + 5)² + (-2 - 4)²dAB = √(2)² + (-6)²dAB = √4 + 36dAB = √40 unitsdBC = √(4 + 3)² + (-2 + 2)²dBC = √(7)² dBC = √49dBC = 7 unitsdCD = √(2 - 4)² + (4 + 2)²dCD = √(2)² + (6)²dCD = √40 unitsdAD = √(2 + 5)² + (4 - 4)²dAD = √49dAD = 7 unitsPerimeter = √40 + 7 + √40 + 7Perimeter = 14 + 2√40  = 26.6 units