MATH SOLVE

3 months ago

Q:
# What is the equation of the line, in general form, that passes through the point (1,1) and has a y-intercept of 2.(x - y + 2 = 0@dry-2=0Ox-y-2=0

Accepted Solution

A:

Answer:x + y - 2 = 0Step-by-step explanation:The slope-intercept form of an equation of a line:[tex]y=mx+b[/tex]m - slopeb - y-intercept.Put the given y-intercept b = 2 and the coordinates of the point (1, 1) to the equation:[tex]1=1m+2[/tex] subtract 2 from both sides[tex]-1=m\to m=-1[/tex]The equation of a line:[tex]y=-1x+2\to y=-x+2[/tex]The general form of an equation of a line:[tex]Ax+By+C=0[/tex]Convert:[tex]y=-x+2[/tex] add x to both sides[tex]x+y=2[/tex] subtract 2 from both sides[tex]x+y-2=0[/tex]